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Energy from the Vacuum

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Subject: Using static voltage source to power a circuit freely
Date: Sun, 14 Oct 2007 11:21:20 -0500

To (correspondent).


Yes, static electricity can indeed be used to freely power things, without ever draining the primary “static voltage” source. One pays a tiny bit of switching costs, and that’s it.


The electrostatic scalar potential (“voltage”) decomposes into bidirectional EM longitudinal waves, per Whittaker’s well-known paper in 1903. So a “static field” or “static potential” is actually a nonequilibrium steady state system of ongoing real EM energy flows.


Hence if you set a “static voltage” on the middle of a real transmission line, the “static voltage” takes off like gangbusters by flowing in both directions nearly at light speed, potentializing the line along both directions. If the static voltage were truly “static”, it could not even move.


If we go to the long-missing asymmetric Maxwellian systems (which by direction of J. P. Morgan were arbitrarily discarded by Lorentz by his symmetrizing the Heaviside equations in 1892), then we can indeed use “static” voltage to potentialize and power a circuit.


Here’s one way. 


Connect a source of static voltage (electrostatic scalar potential or ESP for short) to an external circuit momentarily, while the electrons in the external circuit are deliberately pinned and cannot flow as current. The ESP will flow onto the external circuit, potentializing it, but there will be zero current flow because d/dt = 0 momentarily due to the pinning. (Actually, this flow of ESP changes and potentializes the local vacuum in which the external circuit is embedded, thereby also changing the ongoing interaction between that local vacuum and every one of those pinned charges q in the external circuit). So real potential EM energy is now “stored in the potentialized external circuit – actually, stored in the altered local vacuum but without current or work being yet done).


Now – with the charges q still pinned but with the external circuit potentialized – just switch away the external source of static voltage. At that gap in the external circuit, complete the circuit again with a resistor and diode in series (the diode is oriented in the direction that current will normally “want” to flow once the pinning of the charges is released).  The diode must be oriented properly so that the “closed current loop” is established in one rotational direction.


Then the pinning dies away, so that the electrons can now move and dq/dt current appears in the separated and re-completed external circuit. This NEW and already freely potentialized circuit will now discharge that freely collected potential energy, to power its losses and its loads. The real power developed in the resistor, e.g., can be directly measured.


So in this “new” external (now symmetrized!) circuit that is now unpinned, half the previously collected free potential energy will be dissipated to power the loads and losses (against the forward mmf) and the other half will be dissipated to kill the source dipolarity (where the interaction from the local excited vacuum with the broken symmetry of the dipolarity is actually extracting the EM energy from the vacuum).


So some “free power in the load” will be generated, as the circuit decays and discharges its freely collected potential energy.


Then one disconnects the resistor and diode, reconnects the external circuit to the original static voltage source, repotentializes the external circuit with charges pinned, separates the source and recompletes the external circuit, and iterates the process again. And again. And again.


We have described the operation of an asymmetric system – the kind of Maxwellian systems that Lorentz arbitrarily discarded and that electrical engineering still arbitrarily discards today. Simply check Maxwell’s original theory – 20 quaternion-like equations in 20 unknowns, and it contains both symmetric and asymmetric systems.


Any system that receives and uses excess energy from its local vacuum is a priori an asymmetric system, because it must have and use more forward mmf than the primary source back mmf.


The example given was simply to disconnect the external source while the circuit is still “pinned”, prior to any current being rammed forcibly back through the back emf of the primary source.


This example could be simulated on a good simulation, to show that it indeed will work as advertised.


To get the pinning (of up to a microsecond, e.g.), one could use the primary conductors in the external circuit made of 2% iron doped in 98% aluminum. Such an alloy can be made in a metallurgical lab, in an inert atmosphere.


There are also other ways to do the pinning that sophisticated circuit people already know, and that can be used. The problem has been that the primary circuit people who do and use pinning, also do not remove the primary source.


The “secret” is potentialize statically with the primary static source connected, then dissipate dynamically with the primary static source disconnected and the external circuit re-completed.


Very best wishes,