The Tom Bearden


Subject: RE: Electron relaxation
Date: Wed, 27 Jun 2001 16:44:13 -0500


The "delay" allows you to "statically" charge the beast, get off it with the charger, and then have the "static" charge turn itself automatically into a dynamic dissipation.  It follows that all the scalar potential energy one gets in there, will then be discharged in the circuit's loads and losses.

If you get a millisecond delay, which is possible with that type of material, microwave switching techniques then easily allow you to switch away, and connect the load across that still momentarily "fixed" static charge.  Simply check with someone who is experienced in such switching.  Any high quality electronic technician can do it.


Tom Bearden

In response to a July 4th query as to how to measure the relaxation time:

For openers you can just hit it with a very square-edged pulse, and capture the response time of the current on a good oscilloscope.  Or better yet, I would recommend you check with your local university on how they would recommend measuring it more precisely

Date: Wed, 27 Jun 2001 20:27:35 +0200

I have some contacts who are able to manufacture the Al/Fe alloy (as described by Tom) and will do that in a week or two. But what I need now is  a relatively easy way of measuring the relaxation time of the electrons in the alloy (to test actual relaxation time). I have a couple of ideas:

1. Measuring voltage over a resistor in series with the DSM (degenerate semiconductor material). There shouldn't be a voltage over the resistor  until electrons in the DSM start moving.... or ?
2. Measuring magnetic flux (with a hall-element) in a coil in series with the DSM. There shouldn't be any flux in the coil before electrons  start moving, right ??

One other thing I was thinking about: If I would be able to remove the potential over the DSM before the electrons start moving, there wouldn't  really be any need to wait the same amount of time, i.e. I switch on an FET for say 1 ms, and just have it switched off 1 microsec. Or is the on-time accumulative ??

Please get back a.s.a.p. as I don't have any other source which could provide me with tips on this.