Subject: Using static voltage
source to power a circuit freely Date: Sun, 14 Oct 2007 11:21:20 -0500
Yes, static electricity can indeed
be used to freely power things, without ever draining the primary
“static voltage” source. One pays a tiny bit of switching costs, and
that’s it.
The electrostatic scalar potential
(“voltage”) decomposes into bidirectional EM longitudinal waves, per
Whittaker’s well-known paper in 1903. So a “static field” or “static
potential” is actually a nonequilibrium steady state system of ongoing
real EM energy flows.
Hence if you set a “static
voltage” on the middle of a real transmission line, the “static
voltage” takes off like gangbusters by flowing in both directions
nearly at light speed, potentializing the line along both directions.
If the static voltage were truly “static”, it could not even move.
If we go to the long-missing
asymmetric Maxwellian systems (which by direction of J. P. Morgan were
arbitrarily discarded by Lorentz by his symmetrizing the Heaviside
equations in 1892), then we can indeed use “static” voltage to
potentialize and power a circuit.
Here’s one way.
Connect a source of static voltage
(electrostatic scalar potential or ESP for short) to an external
circuit momentarily, while the electrons in the external circuit are
deliberately pinned and cannot flow as current. The ESP will flow onto
the external circuit, potentializing it, but there will be zero
current flow because d/dt = 0 momentarily due to the pinning.
(Actually, this flow of ESP changes and potentializes the local vacuum
in which the external circuit is embedded, thereby also changing the
ongoing interaction between that local vacuum and every one of those
pinned charges q in the external circuit). So real potential EM energy
is now “stored in the potentialized external circuit – actually,
stored in the altered local vacuum but without current or work being
yet done).
Now – with the charges q still
pinned but with the external circuit potentialized – just switch away
the external source of static voltage. At that gap in the external
circuit, complete the circuit again with a resistor and diode in
series (the diode is oriented in the direction that current will
normally “want” to flow once the pinning of the charges is released).
The diode must be oriented properly so that the “closed current loop”
is established in one rotational direction.
Then the pinning dies away, so
that the electrons can now move and dq/dt current appears in the
separated and re-completed external circuit. This NEW and already
freely potentialized circuit will now discharge that freely collected
potential energy, to power its losses and its loads. The real power
developed in the resistor, e.g., can be directly measured.
So in this “new” external (now
symmetrized!) circuit that is now unpinned, half the previously
collected free potential energy will be dissipated to power the loads
and losses (against the forward mmf) and the other half will be
dissipated to kill the source dipolarity (where the interaction from
the local excited vacuum with the broken symmetry of the dipolarity is
actually extracting the EM energy from the vacuum).
So some “free power in the load”
will be generated, as the circuit decays and discharges its freely
collected potential energy.
Then one disconnects the resistor
and diode, reconnects the external circuit to the original static
voltage source, repotentializes the external circuit with charges
pinned, separates the source and recompletes the external circuit, and
iterates the process again. And again. And again.
We have described the operation of
an asymmetric system – the kind of Maxwellian systems that Lorentz
arbitrarily discarded and that electrical engineering still
arbitrarily discards today. Simply check Maxwell’s original theory –
20 quaternion-like equations in 20 unknowns, and it contains both
symmetric and asymmetric systems.
Any system that receives and uses
excess energy from its local vacuum is a priori an asymmetric system,
because it must have and use more forward mmf than the primary source
back mmf.
The example given was simply to
disconnect the external source while the circuit is still “pinned”,
prior to any current being rammed forcibly back through the back emf
of the primary source.
This example could be simulated on
a good simulation, to show that it indeed will work as advertised.
To get the pinning (of up to a
microsecond, e.g.), one could use the primary conductors in the
external circuit made of 2% iron doped in 98% aluminum. Such an alloy
can be made in a metallurgical lab, in an inert atmosphere.
There are also other ways to do
the pinning that sophisticated circuit people already know, and that
can be used. The problem has been that the primary circuit people who
do and use pinning, also do not remove the primary source.
The “secret” is potentialize
statically with the primary static source connected, then dissipate
dynamically with the primary static source disconnected and the
external circuit re-completed.
Very best wishes, Tom |